ALright.. thanks again!

 

So the limiting reactant for this experiment was the BaCl2

ANd we measured the salt mixture to be 0.9844 g and the mass of precpitate of Ba3(PO4)2 was 0.2267g

 

SO you said to take the moles of limiting reactant and multiply by the molecular weight, so would I take the moles of Ba3(PO4)2 and use the stoich. ratio, which is 3/1 so then multi the moles of Ba3(PO4)2 to get moles of BaCl2

 

So the moles of Ba3(PO4)2 were calculated to be 0.0003766 moles. Then I multiply by 3/1 which is then 0.0011298 moles of BaCl2

then take molar mass of formula weight and multiply to get the mass of  grams of BaCl2·2H2O  which then I would I subtract from the total, which was 0.9844 g to get the Sodium phosphate mass, which then I can calculate the percentages.

 

I hope I am right. I read what you wrote and then I just wanted to make sure I am doing the calculations correctly.

Thanks for your help!!!!