Calculate the energy released in the formation of one mole of MgSe bonds. The radius of the magnesium ion is 1.60 Å and the radius of the selenide ion is 1.26 Å .

 

 

The equation I have to do this is:

 E = k (constant = 2.31 x 10^-28 J m ) x q1 x q2

              / d (in meters)

 

How do you convert amperes to meters????