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General : calculate Kb
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 Message 1 of 3 in Discussion 
From: MSN NicknameN_2006  (Original Message)Sent: 3/4/2008 1:49 PM
A 0.100 M solution of ethylamine (\rm C_2H_5NH_2) has a \rm pH of 11.87. Calculate the K_b for ethylamine
 
So I took the pH and calculated that x = 7.4 x 10^-3 M
 
THen I set up one of those ICE charts:
                  \rm C_2H_5NH_2     + H20  -->   C2H5NH3+  + OH-
Initial               0.100                              ----                  ----
Change             -x M                             + x M                 + x M
EQuil. Concen  0.100 - x M                      x M                  x  M
 
Then I used Kb =  x^2 divided by (0.100- x)
 
My answer was 5.9 x 10^-3 but that is not the right answer.  I don't know where I went wrong


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 Message 2 of 3 in Discussion 
From: MSN Nickname·Steve·Sent: 3/5/2008 1:48 AM
>>  My answer was 5.9 x 10^-3   <<
 
Your method is correct, just a math error at the end.  The answer you got should be 5.9 X 10�? instead of 10�?.  The literature value of Kb for ethylamine is 5.6 X 10�?, so the answer looks good. 
 
 
Steve

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 Message 3 of 3 in Discussion 
From: MSN NicknameN_2006Sent: 3/5/2008 2:56 AM
Ohhhh.. yeah I did it again and realized what I did wrong!
Thanks!