1. ∆S universe = ∆S system + ∆S surrounding
Correct. 
2. ∆S surrounding = –∆(Entropy, H) system / Temperature
This should be, ∆S surrounding = –∆(Enthalpy, ∆H) system / Kelvin Temperature
3. Positive ∆S surrounding indicates an exothermic reaction
This is correct, according to the equation in (2) above. 
When ∆H of the system is negative (–∆Hsys), then ∆Ssurr = �?–∆Hsys / T) = positive value.
(The temperature T in Kelvins is always a positive number.)
4. Positive ∆S universe indicates a spontaneous reaction
Correct. 