Hi Albert, here you go:
Q2. Calculate moles of HCl and moles of NaOH first (moles = volume in liters X molarity).
Then see which is the limiting reactant. That will be the number of moles of HCl neutralized.
The reaction tells us that 56.2 kJ of heat is released per 1 mole of HCl neutralized (the coefficient in front of HCl is one). Therefore your calculation is,
Your moles of HCl neutralized X 56.2 kJ =
1 1 mole HCl
Q3. 1) Calculate the moles of aluminum.
2) Calculate the heat absorbed by the reaction chamber: 1410 J /°C X ΔT
3) Calculate the heat absorbed by the water: (800 g)(ΔT)(4.184 J/g°C)
4) Add the two heats together to get the total heat released by the reaction.
5) Divide the total heat by the moles of aluminum to get the answer in J/mol.
Q12. Convert 73.3 kPa to atm ( 1 atm = 101.325 kPa). Then you can use Boyle's law, P1V1 = P2V2, to calculate V2 (V1 = 22.0 L, P1 = 0.950 atm, P2 = 73.3 kPa converted to atm, V2 = ?).
Q7. Convert the 10 g of CH4 in flask A to moles. The volume is given as 10 L. Now plug into PV = nRT to get the ratio P/T:
P = nR
T V
Once you know P/T, plug in the value of V for flask B and solve for the moles of CO2 gas, n, and then multiply by the molecular weight 44.0095 g/mol to convert to grams. 
Steve
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