That is correct. Now you just have to solve for x. Often you must use the quadratic formula to do that, but in this case you just have to take the square root of both sides.
54.3 = (2x)2 = (2x)2
(0.5 –x)(0.5 �?x) (0.5 �?x)2
7.36885 = 2x
0.5 �?x
2x = 7.36885 (0.5 �?x)
Once you have x, you can get the equilibrium concentrations:
[H2]eq = 0.5 �?x
[I2]eq = 0.5 �?x
[HI]eq = 2x
Once you get these values, do a check by plugging them back into the equilibrium constant expression, Kc = [HI]eq2 / [H2]eq[I2]eq, and see if you get 54.3 or something close to that. 
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