Hi Al, yes, I think you identified the reactions correctly. The NaOH converts the en dihydrochloride to the "free base" form of the diamine which has the nitrogen lone pairs now free to donate to the Co3+ ion:
[H3NCH2CH2NH3]2+, 2Cl- (aq) + 2NaOH (aq) ---> H2NCH2CH2NH2 (aq) + 2NaCl (aq) + 2H2O (l)
The H2O2 oxidation of Co2+ ion to Co3+ ion is:
oxidation Co2+ (aq) ---> Co3+ (aq)
half-rxn
reduction H2O2 (aq) ---> H2O (l)
half-rxn
from which we get
2Co2+ (aq) + H2O2 (aq) + 2H+ ---> 2Co3+ (aq) + 2H2O (l) (acidic solution)
2Co2+ (aq) + H2O2 (aq) ---> 2Co3+ (aq) + 2OH- (aq) (basic solution)
BTW no problem with sub & superscripts... the subscripts are not so bad, just select the text and choose font size 1, not a true subscript but it looks OK. For superscripts, click on the "Use HTML to create your page" link at the bottom of the editing window and enter <sup> and </sup> tags. Co2+ would be Co<sup>2+</sup> in the HTML view. You can do subscripts this was also, using the <sub> tag. H<sub>2</sub>O gives H2O.
Steve
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