MSN Home  |  My MSN  |  Hotmail
Sign in to Windows Live ID Web Search:   
go to MSNGroups 
Free Forum Hosting
 
Important Announcement Important Announcement
The MSN Groups service will close in February 2009. You can move your group to Multiply, MSN’s partner for online groups. Learn More
Chemistry Corner[email protected] 
  
What's New
  
  Welcome Page  
  About This Site  
  Message Boards  
  General  
  Inorganic  
  Organic  
  Pictures  
  Random  
  FOR ALL  
  Handy Symbols  
  Chemistry Humor  
    
  Documents  
  Chemistry Sites I  
  Chemistry Sites II  
  Chemistry Sites III  
  Organic Sites I  
  Organic Sites II  
  Analytical Sites I  
  Analytical Sites II  
  Lesson Plan Sites  
  Online Problems  
  Names & Formulas  
  Naming Exercises  
  Equations I  
  Equations II  
  Eq. Exercises I  
  Eq. Exercises II  
  The Mole I  
  The Mole II  
  Mole Exercises  
  Stoichiometry  
  Stoich. Exercises  
  More Communities  
  School's Out!  
  _________________  
  Site Map  
  
  
  Tools  
 
Inorganic : calorimetry
Choose another message board
View All Messages
  Prev Message  Next Message       
Reply
 Message 11 of 23 in Discussion 
From: MSN NicknameXenonPrincessWarrior  in response to Message 10Sent: 3/3/2006 8:12 PM

forgot!  - sign of course, exothermic. 

<o:p> </o:p>

<o:p> </o:p>

 

OK how about another problem<o:p></o:p>

<o:p> </o:p>

On a visit to the <st1:place w:st="on">Midwest</st1:place>, you find yourself in a freak hailstorm and get hit by a 6 pound piece of hail  You really want to keep this ice chunk as a souvenir so you decide to pack it in dry ice, put it on the plane with you, and stick it in your freezer.  Unfortunately, you only have a frost-free freezer at home.  How long will the piece of hail last (start the timer from when you get bonked on the head in <st1:State w:st="on"><st1:place w:st="on">Iowa</st1:place></st1:State>).  There are lots of different variables to consider so you can do a lot with this problem!<o:p></o:p>

The molar heat capacity of ice is  37.6 J/mol -*C<o:p></o:p>

I figured this to be 6 lb ice ball to be 2721.54 g and 151.06 moles of water.  I am saying the outside temp is -10 C and it took me an hour to pack it in dry ice so I guess it would still be ok?<o:p></o:p>

I think I can get it home without losing any of it to melting.? <o:p></o:p>

so 151.06 mol  x 37.6 J/mol - *C = 5679.86 J/*C  ????<o:p></o:p>

How would I calculate the kJ needed to melt it without a temp change?  I need to know that don't I?<o:p></o:p>

I am still pondering. <o:p></o:p>

 I am thinking the frost free freezer is the key.  Any insight so far?  <o:p></o:p>

 I will keep thinking about it and post back.....<o:p></o:p>

 Thanks<o:p></o:p>



Replies to This Message The number of members that recommended this message.    
     re: calorimetry   MSN Nickname·Steve·  3/4/2006 12:49 AM