NH3 (g) ––� NH3 (aq) ΔH = �4640 J/mol
HCl (g) ––� HCl (aq) ΔH = �5140 J/mol
NH4Cl (s) ––� NH4Cl (aq) ΔH = +15428.82 J/mol
NH3 (aq) +HCl (aq)-->NH4Cl (aq)ΔH = �4718.6 J/mol
------------------------------------------------------
There are 2 NH4Cl(aq) in the third reaction as well as the forth one.Therefore I cancelled one.
Cancelling NH3(aq),HCl(aq),NH3(aq) , NH4Cl(aq) and HCl(aq) gives me:
NH3(g)+HCl(g)+NH4Cl(s)------->NH4Cl(aq)
ΔH= -139069.78J/mol |
Free Forum Hosting
Important Announcement
Prev Message
