NH3 (g) ––�? NH3 (aq) ΔH = �?4640 J/mol
HCl (g) ––�? HCl (aq) ΔH = �?5140 J/mol
NH4Cl (s) ––�? NH4Cl (aq) ΔH = +15428.82 J/mol
NH3 (aq) +HCl (aq)-->NH4Cl (aq)ΔH = �?4718.6 J/mol
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There are 2 NH4Cl(aq) in the third reaction as well as the forth one.Therefore I cancelled one.
Cancelling NH3(aq),HCl(aq),NH3(aq) , NH4Cl(aq) and HCl(aq) gives me:
NH3(g)+HCl(g)+NH4Cl(s)------->NH4Cl(aq)
ΔH= -139069.78J/mol |
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