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Inorganic : The apparent Molecular Weight
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 Message 10 of 12 in Discussion 
From: MSN Nickname·Steve·  in response to Message 9Sent: 1/10/2008 8:06 PM
Yes, the "thermodynamic temperature" uses the Kelvin scale, but here we're talking about whether V is proportional to T or not.  And that depends on the temperature scale you use.
 
This experiment is a demonstration of Charles' law.  Usually, an objective of the experiment is to extend the line to the x-axis where V = 0.  This extrapolated temperature where V is zero on the graph is absolute zero.  That was the "pleasant surprise" I mentioned earlier.  Here's a simple animation of it using Kelvin temperatures: http://www.grc.nasa.gov/WWW/K-12/airplane/aglussac.html.  When the Kelvin temperature is used, the temperature when V = 0 is zero Kelvin.  If the Celsius scale is used, as in your graph, this temperature is _______. 


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     re: The apparent Molecular Weight   MSN NicknameAbalo3  1/11/2008 2:39 PM