Correct on the reaction and the calculation of the moles, but since the reaction stoichiometry is not simply one to one, you need to determine which is the limiting reactant the same way you did before in another problem. Calculate the moles of one of the products such as MgCl2 based on mole of HCl and based on moles of Mg(OH)2. The reactant that gives the lesser moles of the product is the limiting reactant, and the reactant that gives the greater moles of the product is in excess amount, meaning some of it will be left over after the reaction. That's the one that determines whether the solution is acidic or basic after the reaction. |
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