MSN Home  |  My MSN  |  Hotmail
Sign in to Windows Live ID Web Search:   
go to MSNGroups 
Free Forum Hosting
 
Important Announcement Important Announcement
The MSN Groups service will close in February 2009. You can move your group to Multiply, MSN’s partner for online groups. Learn More
Chemistry Corner[email protected] 
  
What's New
  
  Welcome Page  
  About This Site  
  Message Boards  
  General  
  Inorganic  
  Organic  
  Pictures  
  Random  
  FOR ALL  
  Handy Symbols  
  Chemistry Humor  
    
  Documents  
  Chemistry Sites I  
  Chemistry Sites II  
  Chemistry Sites III  
  Organic Sites I  
  Organic Sites II  
  Analytical Sites I  
  Analytical Sites II  
  Lesson Plan Sites  
  Online Problems  
  Names & Formulas  
  Naming Exercises  
  Equations I  
  Equations II  
  Eq. Exercises I  
  Eq. Exercises II  
  The Mole I  
  The Mole II  
  Mole Exercises  
  Stoichiometry  
  Stoich. Exercises  
  More Communities  
  School's Out!  
  _________________  
  Site Map  
  
  
  Tools  
 
Inorganic : Very Confused
Choose another message board
View All Messages
  Prev Message  Next Message       
Reply
 Message 2 of 4 in Discussion 
From: MSN Nickname·Steve·  in response to Message 1Sent: 1/12/2005 8:49 AM
Hi Nayi, just for review, I'll work the first problem in two steps.  The average rate of formation of a product, or consumption of a reactant, is

Average Rate   =   Final Concentration  -  Initial Concentration
                                     Final Time  -  Initial Time
 
 
For the first problem this will be
 

Average Rate
of Disappearance      =      0.9746 M - 0.9986 M    =    -3.03 X 10-5 Ms-1
of Reactant B                         792 s - 0 s
 
 
Note that the value of the average rate is a negative number.  Physically, we cannot actually have a "negative" rate any more than you can go negative 35 miles per hour in a car.  But in this calculation, a negative answer means we are talking about the rate of disappearance of a reactant, while a positive rate indicates we are looking at the rate of formation of a product.  Normally, all rates are expressed as positive numbers and the given information should always clarify what substance in the reaction the rate is based on.  If your book or teacher wants you to put the sign on your rates, just check that it makes sense according to the above convention.
 
The second step is the calculation of the average rate of disappearance of reactant A based on the rate of disappearance of reactant B just calculated.  From the stoichiometry of the reaction, we see that A disappears at one-third of the rate that B does, so the average rate of disappearance of A will be the 1.01 X 10-5 Ms-1 that you got.  The problem should have specifically asked for the rate of disappearance of reactant A.  The phrase "rate of reaction" alone ain't good enough!
 
 
In the second question, it looks like they just want the average rate of disappearance of reactant A, which will be
 
 
Average Rate
of Disappearance      =      0.3187M - 0.3629 M    =    -8.93 X 10-5 Ms-1
of Reactant A                         495 s - 0 s
 
If they wanted the rate of disappearance of reactant B, we would divide our answer by 2 as you did, since the rate of disappearance of B is half the rate of disappearance of A.  But it looks like in this problem, they just want the rate of disappearance of A, 8.93 X 10-5 Ms-1.
 

Just a reminder, once you know the rate of disappearance or appearance of one substance in the reaction, you can calculate the rate for any other substance:
 
 
For the reaction  aA  +  bB  -->  cC  +  dD,
 
(1/a)(Rate of Disappearance of A)  =  (1/b)(Rate of Disappearance of B)

=  (1/c)(Rate of Formation of C)  =  (1/d)(Rate of Formation of D)

and, for example, "Rate of Disappearance of A" is written symbolically as "D [A] / D t" as you did.  To make the signs come out right, you would have to put a negative sign in front of the first two terms (which are rates of disappearance of reactants which should be "negative").  That can be confusing enough, so I personally always simply use positive rate values in these calculations, and put a negative sign in afterwards if it is asked for, if the rate is of the disappearance of something.
 
 
Steve


Replies to This Message The number of members that recommended this message.    
     re: Very Confused   MSN Nickname2122101234  1/12/2005 10:17 PM