The apparent triplet at 0.8 δ would be the CH3 hydrogens at the end of the chain. This signal would integrate for 3H.
Going down the chain toward the carbonyl group, the large signal at 1.3 δ would be the overlapping signals of the next two CH2 hydrogens in the chain. The integration signal looks like it could be for 4H.
The next signal at 1.6 δ would be the next CH2 hydrogens, integrating for 2H.
The signal at 2.4 δ would be the CH2 hydrogens next to the carbonyl group. Spin-spin splitting by the neighboring two CH2 hydrogens would result in a triplet, which would further be doubled by the neighboring aldehyde H. The signal looks more like a triplet, so the coupling constant to the aldehyde H must be small.
Finally, the aldehyde signal at 9.7 δ integrating for 1H should be split by the neighboring CH2 hydrogens into a triplet signal. The signal looks like it might be a narrow triplet, but it's hard to tell with the integration line going right through the peak.
Any branching of the hexanal carbon chain would likely give some clearer signals, such as a clear doublet for a CH3 group in, for example, 3-methylpentanal, but your spectrum has no obvious doublet signals.
So, hexanal seems to me to be a reasonable identification. 
Steve
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