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| | From:  what464 (Original Message) | Sent: 4/19/2008 1:25 AM |
A mixture of Compound A to react with Compound B in the presence of ethanolic potassium hydroxide. After appropriate workup, he obtained the desired and expected organic product, Compound C.
After H1/C13-NMR / IR analysis of Compound A and B, I determined:
Compound A- 3,5-dimethoxybenzaldehyde
Compound B- 4'-butoxyacetophenone
Can you tell what the product (Compound C) is when Compound A and Compound B reacts in presence of ethanolic potassium hydroxide? |
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| | | From: ·Steve· | Sent: 4/19/2008 2:10 AM |
4-butoxyacetophenone has α-hydrogens that will react with the base, KOH, forming the enolate ion which can then react with the carbonyl carbon of 3,5-dimethoxybenzaldehyde in aldol fashion. Steve |
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| | | From: what464 | Sent: 4/19/2008 2:38 AM |
| Can you show me the structure of Compound C? Thanks |
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| | | From: ·Steve· | Sent: 4/19/2008 4:48 AM |
| After the aldol condensation, elimination of water has occurred to give a highly conjugated, α,β-unsaturated ketone. Steve |
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