|
|
 |
Reply
| | | Message 13 of 21 in Discussion |
|
To recap everything from the beginning
1.a. The mass of ascorbic used is 0.05g
b. Moles of ascorbic acid
=0.05g ascorbic * (1 mol ascorbic/ 176.1 g ascorbic)
=2.84 *10^-4 moles
(c) Total volume of standard solution prepared (mL) was 100 ml
d.
d. Ascorbic acid concentration in standard solution (mol/L):
Converting 100 ml= 0.1 L
C6H8O6= 176.12412 g/mole
= 176.12412 g
Find the mole of Ascorbic first:
= 0.05g * (1 mole / 176g)
= 2.83891* 10^-4 mole
Ascorbic acid concentration :
=2.83891*10^-4mole / 0.1 L
=0.002839 M
2.a.Volume of iodine solution added (mL) is 12.35 ml
(b) Concentration of the iodine solution, using the formula M1*V1 = M2*V2 (where V1 and V2 are the volumes of the two concentrated chemical solutions added to the flask)
A little confuse here?????
|
|
|
|
Free Forum Hosting
Important Announcement
Prev Message
