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Message 19 of 21 in Discussion
From:
·Steve·
in response to
Message 16
Sent: 1/17/2008 8:22 PM
Now use this average volume to calculate the iodine molarity. That will be the average molarity. Do it the same way you did before, using M
1
V
1
= M
2
V
2
.
M1V1= M2V2
M2= (0.002839M * 10.0 mL) / 12.35 mL
<–�?Change this volume to 12.3667 mL
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