Li (g) ––�? Li+ (g) + e�?ΔH = +520kJ/mol
F (g) + e�?––�? F�?(g) ΔH = �?28kJ/mol
By reversing:
F (g) + e�?––�? F�?(g) ΔH = �?28kJ/mol
I will get:
F-(g) ---------------> F(g) + e- ΔH = �?28kJ/mol
Writing both reactions again:
Li (g) ––�? Li+ (g) + e�?ΔH = +520kJ/mol
F-(g) ------> F(g) + e- ΔH = �?28kJ/mol
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Li(g) + F-(g)----------------> ΔH =+192 kJ/mol
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