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| | | Message 8 of 9 in Discussion |
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Li (g) ––� Li+ (g) + e�ΔH = +520kJ/mol
F (g) + e�––� F�(g) ΔH = �28kJ/mol
By reversing:
F (g) + e�––� F�(g) ΔH = �28kJ/mol
I will get:
F+(g) ---------------> F-(g) - e- ΔH = �28kJ/mol
Writing both reactions again:
Li (g) ––� Li+ (g) + e�ΔH = +520kJ/mol
F-(g) ------> F(g) + e- ΔH = �28kJ/mol
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Li(g) + F-(g)--------->Li +(g) + F(g) ΔH =+192 kJ/mol
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