MSN Home  |  My MSN  |  Hotmail
Sign in to Windows Live ID Web Search:   
go to MSNGroups 
Free Forum Hosting
 
Important Announcement Important Announcement
The MSN Groups service will close in February 2009. You can move your group to Multiply, MSN’s partner for online groups. Learn More
Chemistry Corner[email protected] 
  
What's New
  
  Welcome Page  
  About This Site  
  Message Boards  
  General  
  Inorganic  
  Organic  
  Pictures  
  Random  
  FOR ALL  
  Handy Symbols  
  Chemistry Humor  
    
  Documents  
  Chemistry Sites I  
  Chemistry Sites II  
  Chemistry Sites III  
  Organic Sites I  
  Organic Sites II  
  Analytical Sites I  
  Analytical Sites II  
  Lesson Plan Sites  
  Online Problems  
  Names & Formulas  
  Naming Exercises  
  Equations I  
  Equations II  
  Eq. Exercises I  
  Eq. Exercises II  
  The Mole I  
  The Mole II  
  Mole Exercises  
  Stoichiometry  
  Stoich. Exercises  
  More Communities  
  School's Out!  
  _________________  
  Site Map  
  
  
  Tools  
 
Organic : Intermolecular forces
Choose another message board
View All Messages
  Prev Message  Next Message       
Reply
 Message 8 of 9 in Discussion 
From: MSN Nicknamebobbysgirl210  in response to Message 1Sent: 4/11/2008 1:05 AM
Steve, I have some other problems that I have worked through kinda that I need your help on, if possible. The instructions: Think of your body as a large molecule with your hand, feet, ears, etc as functional groups. Discuss how a utensil such as a fork is designed to work with one or 'functional' groups. Relate this to one of the reactions. So here is what I have: 
Parts of the human body can be regarded as functional groups. In this event, alcohol can be thought of as one of these groups. When you think of your body as a whole, different parts can do certain functions. Let’s take the feet. The feet can be compared to aldehydes, ketones, and carbolytic acids.There are things only the feet can do. Take the toes away and it can perform new functions, but loses a part of the old function. An oxidation reaction involves the loss of hydrogen compared to the foot losing toes. Oxidation of a primary alcohol produces an aldehyde, of a secondary alcohol produces a ketone, and tertiary alcohols cannot be oxidized. Compared to the oxidation reaction, in order to occur, they must contain at least one C-H bond. Because tertiary alcohols contain three C-C bonds to the carbinol carbon, they cannot undergo oxidation.
 
The second problem is this:Choose two functional groups and for each group find a household product that contains the functional groups you chose (e.g. fingernail polish remover contains acetone a ketone). Explain the action of the product in terms of the intermolecular forces that these groups impart to the molecule. I have:
The hydroxyl group makes alcohols more soluable (polar) in solvents than the hydrocarbon from which they were derived. Alcohols are capable of hydrogen bonding between molecules. Being very polar, they are able to form intermolecular hydrogen bonds. The alcohol found in alcoholic beverages is ethanol. The oxygen and hydrogen group on the molecule is what gives it the specific chemical properties of alcohol.
The carboxylic acid group makes acetic acid hydrophilic and mixable in water, ethyl alcohol, and diethyl ether because of hydrogen bonding interactions. The hydrogen atom in the carboxyl group can be given off as an H+ ion giving vinager the acidic character.
Any help you are willing to give me is greatly appreciated.
Thanks, meri


Meri Salcedo


You rock. That's why Blockbuster's offering you one month of Blockbuster Total Access, No Cost.


Replies to This Message The number of members that recommended this message.    
     re: Intermolecular forces   MSN Nickname·Steve·  4/11/2008 6:06 AM