>> mass of benzoic acid required to react in stoichiometric proportion with 20 mL of the NaOH solution (MW of benzoic acid =122.12 g/mol) <<
Since this is a 1:1 reaction, moles of NaOH = moles of benzoic acid.
moles of NaOH = volume in liters X molarity = 0.020 L X 0.500 mol/L = 0.010 mol of NaOH.
moles of benzoic acid = moles of NaOH = 0.010 mol.
grams of benzoic acid = moles X molar mass = 0.010 mol X 122.12 g/mol = 
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