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Inorganic : Very Confused
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 Message 1 of 4 in Discussion 
From: MSN Nickname2122101234  (Original Message)Sent: 1/11/2005 3:01 AM

Hey everyone! I’m a bit confused on a rate of chemical reaction calculation�?This is from Petrucci’s “General Chemistry�?textbook:

There’s an example question in the book that is as follows:

A + 3B -> 2C + 2D
[B]= 0.9986 M and 13.20 min later [B]=0.9746 M. What is the average rate of reaction during this time period, expressed in Ms-1.

The answer given is 1.01x 10-5 Ms-1
Since the rate of reaction = (-1/3 )([B]/t)= -(1/3)((0.9746M- 0.9986)/ 792s) = 1.01 X10 -5Ms-1.

Alright, so I understood this question and attempted one of the practice this question:

2A+ B-> C+ D

[A]= 0.3629 M. At a time 8.25 min later {A}= 0.3187M. What is the average rate of the reaction?

I did this question the exact same way as the practice example and I got 4.46X 10 -5Ms-1.

Rate of reaction= -(1/2)( [A]/t) = - (1/2)((0.3187M-0.3629M)/ 495s) = 4.46X 10 -5Ms-1

But it turned out my answer was wrong. According the answer book:

Rate of reaction= -�?[A]/ t = - (0. 3187M-0.3629M)/ 8.25 min x 1 min/60s = 8.93X 10 -5Ms-1

I’m confused. When am I supposed to use the ratio and when do I not use it? Or is this a text book error?

Sorry for the long post! Thanks

Note: I had problems putting up this post, sorry.The "�? are supposed to be deltas.


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Reply
 Message 2 of 4 in Discussion 
From: MSN Nickname·Steve·Sent: 1/12/2005 8:49 AM
Hi Nayi, just for review, I'll work the first problem in two steps.  The average rate of formation of a product, or consumption of a reactant, is

Average Rate   =   Final Concentration  -  Initial Concentration
                                     Final Time  -  Initial Time
 
 
For the first problem this will be
 

Average Rate
of Disappearance      =      0.9746 M - 0.9986 M    =    -3.03 X 10-5 Ms-1
of Reactant B                         792 s - 0 s
 
 
Note that the value of the average rate is a negative number.  Physically, we cannot actually have a "negative" rate any more than you can go negative 35 miles per hour in a car.  But in this calculation, a negative answer means we are talking about the rate of disappearance of a reactant, while a positive rate indicates we are looking at the rate of formation of a product.  Normally, all rates are expressed as positive numbers and the given information should always clarify what substance in the reaction the rate is based on.  If your book or teacher wants you to put the sign on your rates, just check that it makes sense according to the above convention.
 
The second step is the calculation of the average rate of disappearance of reactant A based on the rate of disappearance of reactant B just calculated.  From the stoichiometry of the reaction, we see that A disappears at one-third of the rate that B does, so the average rate of disappearance of A will be the 1.01 X 10-5 Ms-1 that you got.  The problem should have specifically asked for the rate of disappearance of reactant A.  The phrase "rate of reaction" alone ain't good enough!
 
 
In the second question, it looks like they just want the average rate of disappearance of reactant A, which will be
 
 
Average Rate
of Disappearance      =      0.3187M - 0.3629 M    =    -8.93 X 10-5 Ms-1
of Reactant A                         495 s - 0 s
 
If they wanted the rate of disappearance of reactant B, we would divide our answer by 2 as you did, since the rate of disappearance of B is half the rate of disappearance of A.  But it looks like in this problem, they just want the rate of disappearance of A, 8.93 X 10-5 Ms-1.
 

Just a reminder, once you know the rate of disappearance or appearance of one substance in the reaction, you can calculate the rate for any other substance:
 
 
For the reaction  aA  +  bB  -->  cC  +  dD,
 
(1/a)(Rate of Disappearance of A)  =  (1/b)(Rate of Disappearance of B)

=  (1/c)(Rate of Formation of C)  =  (1/d)(Rate of Formation of D)

and, for example, "Rate of Disappearance of A" is written symbolically as "D [A] / D t" as you did.  To make the signs come out right, you would have to put a negative sign in front of the first two terms (which are rates of disappearance of reactants which should be "negative").  That can be confusing enough, so I personally always simply use positive rate values in these calculations, and put a negative sign in afterwards if it is asked for, if the rate is of the disappearance of something.
 
 
Steve

Reply
 Message 3 of 4 in Discussion 
From: MSN Nickname2122101234Sent: 1/12/2005 10:17 PM
O I get it! Thanks for clearing that up for me Steve!

Reply
 Message 4 of 4 in Discussion 
From: MSN Nickname·Steve·Sent: 1/13/2005 6:18 AM
No prob!

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