In a Lab, for my Chemistry paper, we had to prepare a racemic mixture of [Co(en)3]Cl3. We then had to resolve the enantiomers by forming diastereoisomers with tartaric acid. The thing is, for the lab report we have to write the series of equations for the reactions that took place. I have no problem understanding the resolution and the isomerism, it's the actual reactions to form the [Co(en)3]Cl3.
We dissolved CoCl2.6H2O and en.2HCl (en=ethylenediamine) in water. To this we added NaOH and then H2O2, followed by more water. We precipitated out some crystals with the help of an ice bath, then dried them with a Büchner funnel. These crystals are rac-[Co(en)3]Cl3.0.5NaCl.3H2O.
As far as I can tell: the NaOH removes the HCl from the en.2HCl and the H2O2 oxidises the Co(II) to Co(III), thus making the formation of the complex possible. I would really appreciate some help with this.
Cheers, Al.
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