I believe this the end for this part of the problem
4. From your two or more best "fine" titrations, calculate the average iodine concentration, thus determining today's standard value for the iodine solution.
M1V1 = M2V2.
M1V1= M2V2
M2= (0.002839M * 10.0 mL) / 12.3667 mL
= 0.0022957M
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